Answer:y=(1-5x+5C)/(C-x)Step-by-step Explanation:dy − (y − 5)^2 dx = 0Add (y-5)^2 dx on both sides:dy=(y-5)^2 dxDivide both sides by (y-5)^2:dy/(y-5)^2=dxWe have separated the variables and are thus ready to integrate:(y-5)^(-1)/(-1)+C=x-1/(y-5) + C=xPerhaps you want to solve for y:Multiply both sides by (y-5):-1+C(y-5)=x(y-5)Subtract C(y-5) on both sides:-1=x(y-5)-C(y-5)Distribute:-1=xy-5x-Cy+5CGroup y terms together:-1=-5x+5C+xy-CyFactor the y out from the terms containing y:-1=-5x+5C+y(x-C)Subtract 5C and -5x on both sides:-1--5x-5C=y(x-C)Divide both sides by (x-C):(-1+5x-5C)/(x-C)=yMultiply by 1=-1/-1:(1-5x+5C)/(C-x)=yy=(1-5x+5C)/(C-x)